Number foundations & fractions · Lesson 1 of 1

Fractions and ratio

Adding, subtracting, multiplying and dividing fractions and mixed numbers, the order of operations, fraction-of-the-remainder problems, sharing and combining ratios, average speed, HCF and LCM, and decimals.

29 min
  1. 1

Almost every WAEC Paper 2 starts with a fraction to simplify “without using tables or a calculator”. It’s easy marks if you set out each step carefully.

Try it

Fractions on barsChange the fractions
2/31/4=both cut into 12 equal pieces
2/3 + 1/4 = 11/12with denominator 12: 8/12 + 3/12
Pieces must be the same size before you can add them. Cut both bars into 12 pieces (the lowest common multiple of 3 and 4): 2/3 = 8/12 and 1/4 = 3/12. Then 8 + 3 = 11 pieces: 11/12.

To add or subtract, the pieces must be the same size. So cut both bars into the same number of pieces: the lowest common multiple (LCM) of the denominators. Switch to Divide to see why dividing by a fraction is the same as turning it over and multiplying.

The four operations

OperationMethod
add, subtractchange to a common denominator, then add or subtract the tops
multiplymultiply the tops and multiply the bottoms (cancel first)
divideturn the second fraction over, then multiply
mixed numberschange to improper fractions first: 234=1142\frac34 = \frac{11}{4}

The word “of” means multiply: 13\frac13 of 25\frac25 is 13×25=215\frac13 \times \frac25 = \frac{2}{15}. In the order of operations below, “of” counts as a multiplication.

Order of operations

Work in this order: brackets first, then powers, then division and multiplication, then addition and subtraction. The word BODMAS helps you remember it. In a big fraction, work out the top and the bottom separately, then divide.

Worked example · WAEC 2017

WAEC 2017 · Paper 2 · Q1 (a)

Simplify: 212+134÷125214−112\dfrac{2\frac12 + 1\frac34 \div 1\frac25}{2\frac14 - 1\frac12}.

  1. The top: divide before adding

    • Division first: 134÷125=74÷75{1\frac34 \div 1\frac25 = \frac74 \div \frac75}.
    • Turn over and multiply: 74×57=54{\frac74 \times \frac57 = \frac54}.
    • Then add: 212+54=104+54=154{2\frac12 + \frac54 = \frac{10}{4} + \frac54 = \frac{15}{4}}.

    Think first. Which comes first in 212+134÷1252\frac12 + 1\frac34 \div 1\frac25?

  2. The bottom

    • 214−112=94−64{2\frac14 - 1\frac12 = \frac94 - \frac64}.
    • =34{= \frac34}.
  3. Divide top by bottom

    • 154÷34=154×43{\frac{15}{4} \div \frac34 = \frac{15}{4} \times \frac43}.
    • The 4s cancel: 153=5{\frac{15}{3} = 5}.

More: simplifying fractions

“A fraction of the remainder”

Many word problems spend fractions of an income one after another. Keep track of what’s left at each step. A fraction “of the remainder” is a fraction of what’s left, not of the whole.

¼⅓⅙¼ leftthe remainder, 5⁄12⅖ of 5⁄12 = ⅙ of the wholethe whole income
A fraction of the remainderTake the fraction of what's left, not of the whole

Worked example · WAEC 2020

WAEC 2020 · Paper 2 · Q8 (a)

Ms. Maureen spent 14\frac14 of her monthly income at a shopping mall, 13\frac13 at an open market and 25\frac25 of the remaining amount at a mechanic workshop. If she had ₦225,000.00 left, find: (i) her monthly income; (ii) the amount spent at the open market.

  1. The first two spends

    • Spent: 14+13=312+412=712{\frac14 + \frac13 = \frac{3}{12} + \frac{4}{12} = \frac{7}{12}}.
    • Left: 1−712=512{1 - \frac{7}{12} = \frac{5}{12}}.

    Think first. What fraction of her income is left after the mall and the market?

  2. Two-fifths of the remainder

    • The workshop takes 25×512=16{\frac25 \times \frac{5}{12} = \frac16} of her income.
    • Left: 512−16=512−212=14{\frac{5}{12} - \frac16 = \frac{5}{12} - \frac{2}{12} = \frac14}.
  3. (i) The income

    • 14\frac14 of her income is ₦225,000.
    • So her income is 4×225 000{4 \times 225\,000}, which is ₦900,000.
  4. (ii) The open market

    13×900 000=\frac13 \times 900\,000 = ₦300,000.

More: fractions of the remainder

Ratio

To share an amount in the ratio a:b:ca : b : c:

  1. add the parts, a+b+ca + b + c;
  2. find what one part is worth;
  3. multiply by each person’s number of parts.

To combine p:qp : q and q:rq : r, make the qq parts equal. Take p:q=2:3p : q = 2 : 3 and q:r=4:5q : r = 4 : 5:

  • multiply the first by 4: 8:128 : 12;
  • multiply the second by 3: 12:1512 : 15;
  • now qq is 12 in both, so p:q:r=8:12:15p : q : r = 8 : 12 : 15.

If a ratio is given in fractions, first multiply through by the LCM of the denominators to get whole numbers.

p : qq : r2 : 34 : 58 : 1212 : 15× 4 ↓× 3 ↓p : q : r = 8 : 12 : 15
Combining two ratiosMake the shared letter the same size in both

More: ratio

Average speed

A speed is a rate: distance per unit of time, such as kilometres per hour (km/h). For a journey in several parts, the average speed is

average speed=total distancetotal time\text{average speed} = \frac{\text{total distance}}{\text{total time}}
DST
Speed, distance, timeD = S × T, S = D ÷ T, T = D ÷ S
60 km, 2 h60 km, 3 hat 30 km/hat 20 km/h120 km ÷ 5 h = 24 km/hnot (30 + 20) ÷ 2 = 25
Average speedTotal distance ÷ total time, not the average of the speeds

It is not the average of the speeds, because the slower part takes longer. For example, drive 120 km at 60 km/h and come back at 40 km/h:

  • There: 120÷60=2{120 \div 60 = 2} hours.
  • Back: 120÷40=3{120 \div 40 = 3} hours.
  • Total: 240 km in 5 hours.
  • Average speed: 240÷5=48{240 \div 5 = 48} km/h, not (60+40)÷2=50{(60 + 40) \div 2 = 50}.

Worked example · WAEC 2010

WAEC 2010 · Paper 2 · Q11 (b)

A motorist travelled 300 km300\text{ km} at an average speed of 75 km/h75\text{ km/h} and returned at an average speed of v km/hv\text{ km/h}. If his average speed for the whole journey is 60 km/h60\text{ km/h}, find vv.

  1. The total distance

    • There and back: 300+300=600{300 + 300 = 600} km.

    Think first. How far is there and back?

  2. The total time

    • 600÷60=10{600 \div 60 = 10} hours for the whole journey.

    Think first. Use time = distance ÷ speed with the average speed.

  3. The time for each way

    • Outward: 300÷75=4{300 \div 75 = 4} hours.
    • Return: 10−4=6{10 - 4 = 6} hours.

    Think first. How long does the outward trip take at 75 km/h?

  4. The return speed

    • v=300÷6=50{v = 300 \div 6 = 50}.

    Think first. Speed = distance ÷ time for the return trip.

Factors, primes, HCF and LCM

A prime number has exactly two factors, 1 and itself: 2, 3, 5, 7, 11, 13 and so on. (1 is not prime.) Every whole number can be written as primes multiplied together, and a factor tree finds them.

728924332272 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
A factor treeSplit until every branch ends in a prime
12182233HCF = 2 × 3 = 6; LCM = 2 × 2 × 3 × 3 = 36
HCF and LCMCommon primes give the HCF; all of them give the LCM
  • The HCF (highest common factor) multiplies the primes the numbers share.
  • The LCM (lowest common multiple) multiplies every prime needed, each as often as it appears in any one number.
  • A perfect square has every prime an even number of times. 72=23×3272 = 2^3 \times 3^2 needs one more 2. So the smallest number to multiply 72 by to get a perfect square is 2, giving 144=122144 = 12^2.

More: factors, primes, HCF and LCM

Fractions and decimals

  • To compare fractions and decimals, change them all to decimals: 58=0.625\frac58 = 0.625.
  • To divide by a decimal, multiply the top and bottom by 10, 100 or 1000 until the bottom is whole: 10.03=1003\frac{1}{0.03} = \frac{100}{3}.
  • In a place-value sum, 31000\frac{3}{1000} is the third decimal place: 0.0030.003.

More: fractions and decimals

Your turn

WAEC 2023 · Paper 2 · Q7 (a)

  1. (a)

    Aman spent 13\frac13 of his income on rent, 16\frac16 of the income in a fast food shop and 34\frac34 of the remaining amount was saved in a bank. If he had ₦125,000.00 left, find: (i) his income; (ii) the amount saved in the bank.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. Rent and food take 13+16=12\frac13 + \frac16 = \frac12 of his income, leaving 12\frac12.
  2. He saves 34\frac34 of that: 34×12=38\frac34 \times \frac12 = \frac38.
  3. What's left is 12−38=18\frac12 - \frac38 = \frac18 of his income.

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