Logarithms · Lesson 2 of 2

Using four-figure tables

Reading logarithm and antilogarithm tables, bar notation for numbers less than 1, and using logs to multiply, divide and take roots, as some questions still require.

15 minYou should already know: Indices & standard form
  1. 1
  2. 2

Most questions now say “without using tables”, and a calculator does the rest. A few still ask you to “use mathematical tables”, and then the working must show the table steps. This lesson is for those questions.

The logarithm of a number

Every log has two parts:

  • the characteristic, the whole-number part: the power of 10 when the number is in standard form;
  • the mantissa, the decimal part: read from the table, and always positive.

For example, take 75.975.9:

  • in standard form it is 7.59×1017.59 \times 10^1, so the characteristic is 1;
  • the table entry for 7.59 is .8802.8802, which is the mantissa;
  • so log⁡75.9=1.8802\log 75.9 = 1.8802.
Four-figure tables: logarithmsPick a number
N01234
3959115922593359445955
4060216031604260536064
4161286138614961606170
4.000 × 10³standard form3characteristic (the power of 10).6021mantissa: 60213.6021log 4000
In standard form, 4000 = 4.000 × 103, so the characteristic is 3. Look up 40 in the first column, go across to column 0. The mantissa is always positive; only the characteristic can carry a bar.

To read the table:

  • the row is the first two figures (75);
  • the column is the third figure (9);
  • if there is a fourth figure, add the mean difference for it, from the small columns on the right.

A printed table has ten main columns, 0 to 9, and nine mean-difference columns headed 1 to 9. The board shows only the part you need.

Numbers less than 1: bar notation

0.04735=4.735×10−20.04735 = 4.735 \times 10^{-2}, so the characteristic is −2-2. The mantissa stays positive, so the minus sign is written above the characteristic, as a bar:

log⁡0.04735=2ˉ.6754=−2+0.6754\begin{aligned} \log 0.04735 &= \bar{2}.6754 \\ &= -2 + 0.6754 \end{aligned}
−3−2−10+ 0.6754−1.32462̄ = −2
Bar notation2̄.6754: start at −2, then go forward 0.6754

Antilogarithms: back to the number

Look up the mantissa in the antilog table (row, column, mean difference) to get the figures. Then use the characteristic to place the decimal point. For 2ˉ.6749\bar{2}.6749:

  • the antilog table gives the figures 4731 for .6749.6749;
  • the characteristic 2ˉ\bar{2} means ×10−2\times 10^{-2};
  • so the number is 4.731×10−2=0.047314.731 \times 10^{-2} = 0.04731.

Calculating with logs

Todo this to the logs
multiplyadd them
dividetake them away
find a powermultiply the log by the power
find a rootdivide the log by the root

Then take the antilog of the result. Set the working out in a table.

Worked example · NECO 2024

NECO 2024 · Paper 2 · Q6 (a)

Use mathematical tables to evaluate 40004×75.95.61×4.39\dfrac{\sqrt[4]{4000} \times 75.9}{5.61 \times 4.39}.

  1. The fourth root

    log⁡4000=3.6021\log 4000 = 3.6021. Divide by 4 for the fourth root: 0.90050.9005.

    Think first. How do you take a fourth root with logs?

  2. The numerator

    log⁡75.9=1.8802\log 75.9 = 1.8802. Add: 0.9005+1.8802=2.78070.9005 + 1.8802 = 2.7807.

  3. The denominator

    log⁡5.61=0.7490\log 5.61 = 0.7490 and log⁡4.39=0.6425\log 4.39 = 0.6425. Add: 1.39151.3915.

  4. Divide and take the antilog

    • Top minus bottom: 2.7807−1.3915=1.3892{2.7807 - 1.3915 = 1.3892}.
    • The antilog of .3892{.3892} gives the figures 2450.
    • The characteristic 1 means ×101{\times 10^1}, so the answer is about 24.50.

Dividing a bar characteristic

To halve 1ˉ.5540\bar{1}.5540, you can’t just halve the 1ˉ\bar{1}: half of −1-1 isn’t a whole number. So first borrow 1 to make the characteristic even:

  • borrow 1, since −1=−2+1{-1 = -2 + 1}: 1ˉ.5540=2ˉ+1.5540{\bar{1}.5540 = \bar{2} + 1.5540};
  • halve each part: 1ˉ+0.7770{\bar{1} + 0.7770};
  • so half of 1ˉ.5540{\bar{1}.5540} is 1ˉ.7770{\bar{1}.7770}.

Your turn

WAEC 2025 · Paper 2 · Q6 (a)✱✱

  1. (a)

    Using mathematical tables, find: (i) 2sin⁡63.35∘2\sin63.35^\circ; (ii) log⁡(cos⁡44.74∘)\log(\cos44.74^\circ); (iii) kk, given that log⁡k−log⁡(k−2)=log⁡5\log k - \log(k - 2) = \log 5.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)(i)

  1. From the tables, sin⁡63.35∘≈0.8938\sin 63.35^\circ \approx 0.8938, so 2sin⁡63.35∘≈1.7882\sin 63.35^\circ \approx 1.788.

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